(a) `2` Calculate the number of moles of water in `366 g BaCl_(2).2H_(2)O`.
(b) Calculate the value of `X` ( in terms of mole) if `X=9.4 g "Phenol" +6.02xx10^(22)` molecules phenol `+0.2 "mole"` phenol.

Explanation

(a) Mol.wt.of `BaCl_(2).2H_(2)O- 244 g`
`:' 244 g BaCl_(2).2H_(2)O= 36 gH_(2)O=2 "mole of" H_(2)O`
`:. 366 BaCl_(2).2H_(2)O=(2xx366)/(244) "mole of" H_(2)O`
`3 "mole of" H_(2)O`
(b) `X=(9.4)/(94)"mole"+(6.02xx10^(22))/(6.02xx10^(23))"mole"+0.2d "mole"`
`:' = 0.1+0.1+0.2= 0.4 "mole"`