`5.325 g` sample of methyl benzoate, a compound used in the manufacture of perfumes is found to contain `3. 758 g` of carbon, `0.316 g` of hydrogen and `1.251 g` of oxygen. What is empirical formula of compound. If mol. Weight of methyl benzoate is `136.0`, calculate its molecular formula.

Explanation

`|{:("Element",%,"Mole ration","Simplest mole ratio"),(C,(3.758xx100)/(5.325)=70.57,(70.57)/(12)=5.88,(5.88)/(1.47)=4),(H,(0.316xx100)/(5.325) =5.93,(5.93)/(1)=5.93,(5.93)/(1.47)=4),(O,(1/252xx100)/(5.325)=23.50,(23.50)/(16)=1.47,(1.47)/(1.47)=1):}:|`
`:.` Empirical forumula is `C_(4)H_(4)O`
Also empirical formula weight
`=4xx12+4xx1+16= 68`
`:' n(mol.wt)/("empirical formula wt.")=(136)/(68)=2`
`:.` Molecular formula of methyl benzonate is `(C_(4)H_(4)O)_(2)` or `C_(8)H_(8)O_(2)`.