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In a reaction vessel 0.184 g of NaOH is ...

In a reaction vessel `0.184 g` of `NaOH` is required to be added for completing the reaction. How many millilitre of `0.150M NaOH` solution should be added for this requirements?

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Milli-mole `=MxxV_("in"mL)`
`(0.184)/(4)xx100= 0.150xxV`
`V_(NaOH)= 30.67mL`
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