An antifreeze solution is prepared from `222.6 g` of ethylene glycol `[C_(2)H_(4)(OH)_(2)]` and `200 g` of water. Calculate the molality of the solution. If the density of the solution is `1.072g mL^(-1)` then what shall be the molarity of the solution?

Explanation

To solve the problem step by step, we need to calculate the molality of the solution first and then find the molarity.

### Step 1: Calculate the number of moles of ethylene glycol (C₂H₄(OH)₂)

1. **Find the molar mass of ethylene glycol (C₂H₄(OH)₂)**:
- Carbon (C): 12.01 g/mol × 2 = 24.02 g/mol
- Hydrogen (H): 1.008 g/mol × 6 = 6.048 g/mol
- Oxygen (O): 16.00 g/mol × 2 = 32.00 g/mol
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