The concentration of `Fe^(2+)` ion in aqueous solution can be determined by redox titration with bromate ion according to reaction:
`6Fe_((aq))^(2+)+BrO_(3(aq))^(-)+6H_((aq))^(+)rarr6Fe_((aq))^(3+)+Br_((aq))^(-)+3H_(2)O_((l))`
What is the molar concentration of `Fe^(2+)` if `31.50mL` of `0.105 M KBrO_(3)` is required for complete neutralisation of `10.0mL` of `Fe^(2+)` solution?

Explanation

Milli-mole of `Fe^(2+)=`Milli-mole of `BrO_(3)^(-)xx6`
(Follow mole ration)
`Mxx10 = 31.50xx0.105xx6`
`M_(Fe^(2+))= 1.945`