Potassium superoxide `KO_(2)`, is utillised in closed system breathing apparatus. Exhaled air contains `CO_(2)` and `H_(2)O`, both of which are removed and the removal of water generates oxygen for breathing by the reaction
`4KO_(2(s))+2H_(2)O_((l))rarr 3O_(2(g))+ 4KOH_((s))`
The potassium hydroxide removes `CO_(2)` from the apparatus by the reaction:
`KOH_((s))+CO_(2(g))rarr KHCO_(3(s))`
(a) What mass of `KO_(2)` generates `20 gm` of oxygen?
(b) What mass of `CO_(2)` can br removed from the apparatus by `CO_(2)` can be removed from the apparatus by `100gm` of `KO_(2)`?

Explanation

`4KO_(2)+2H_(2)O_(l)rarr3O_(2(g))+4KOH_((s))`
`KOH_((s))+CO_(2(g))rarrKHCO_(3(s))`
(a) mole ration `4"mole"KO_(2)-=3"mole"O_(2)`
`4xx71 gKO_(2)=3xx32gO_(2)`
`:. 20 g O_(2)` is generated by `=(4xx71)/(3xx32)xx20`
`= 59.17 g KO_(2)`
(b) `4 "mole" KO_(2)-= 4"mole"KOH`
`(100)/(71)"mole"KO_(2)=(100)/(71)"mole"KOH`
`=(100)/(71)xx5.6KOH`
`=78.9g KOH`
`56 KOH` removes`=44 g CO_(2)`
`78.9 gKOH` removes `=(44)/(56)xx78.9`
`=61.97 g CO_(2)`