How much `CO` is produced by the reaction of `1.0 kg` octane and `1.0 kg` oxygen. Also report the limiting reagent for this reaction.

Explanation

`{:(,C_(8)H_(18)+,(17)/(2)O_(2)rarr,8CO+,9H_(2)O),("Moles before reaction",(10^(3))/(114),(10^(3))/(32),,),("Moles after reaction",[10^(3)/(114)-(10^(3)xx2)/(32xx17)],0,(8xx10^(3)xx2)/(32xx17),):}`
Mole ratio for reaction is `C_(8)H_(18):O_(2)::1:(17)/(2)`
and `O_(2):CO::(17)/(2):8`
Thus, `O_(2)` is limiting reagent and moles of `CO` formed `= 29.41`
Mass of `CO` formed `= 29.41xx28= 823.48 g`