A one litre solution `0.2M Mg(NO_(3))_(2), 0.2M Al(NO_(3))_(3)` and `0.5M Th (NO_(3))_(4)`. What is the total ionic strength of solution?

Explanation

The ionic strength `(mu)` of solution is given by:
`mu=(1)/(2)SigmaCZ^(2)`
Where `C` is concentration of ion and `Z` is its valence.
`:. Mu =(1)/(2)[0.2xx2^(2)+0.2xx1^(2)+0.2xx3^(2)+0.2xx1^(2)+0.5xx4^(2)+0.5xx1^(2)]`
`=(1)/(2)[11.5]=5.75`