Calculate the volume of `1.00 mol L^(-1)` aqueous sodium hydroxide that is neutralized by `200 mL` of `2.00 mol L^(-1)` aqueous hydrochloric acid and the mass of sodium chloride produced. Neutralization reaction is,
`NaOH_((aq.))+HCl_((aq.))rarr NaCl_((aq.))+H_(2)O_((l))`

Explanation

Meq. of `NaOH=Meq. "of" HCl=Meq."of" NaCl`
`NxxV_(mL)=NxxV_(mL)`
`(N_(HCl)=M_(HCl), Na_(NaOH)=M_(NaOH))`
`1xxV=2xx200`
`:. V= 400 mL`
Meq. Of `NaCl=2xx200=400`
`:. (w)/(58.5)xx1000=400`
`:. W_(NaCl)=23.4 g`