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Calculate the molality of 1 L solution o...

Calculate the molality of `1 L` solution of `93% H_(2)SO_(4)` (Weight/volume) The density of the solution is `1.84 g`.

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Verified by Experts

Given, `H_(2)SO_(4)` is `93%` by volume.
`:. "Wt.of" H_(2)SO_(4)= 93 g`
Volume of solution `=100 mL`
`:.` Wt. of solution `= 100xx1.84=184 g`
`:.` Wt. of water `=184-93=91 g`
`:. "Molality"=("Mole")/("Wt.ofwater in" kg)`
`=(93)/(98xx(91)/(1000))=10.42`
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