Calculate the number of oxalic acid molecules in `100 mL` of `0.02 N` oxalic acid

Explanation

Normality `= 0.02`
`:.` Molarity `= (0.02)/(2)` (`because` valency factor `=2`)
`:.` Mole of oxalic acid `= (0.02)/(2) xx (100)/(1000)`
(`because` mole `= M xx V_(l)`)
`:.` No. of molecules of oxalic acid
`= 0.001 xx 6.023 xx 10^(23) = 6.023 xx 10^(20)`