Home
Class 11
CHEMISTRY
One litre of N//2 HCl solution was heate...

One litre of `N//2 HCl` solution was heated in a beaker. When the volume was reduced to `600 mL`, `9.125 g` of `HCl` was lost out. The new normality of solution is
a. `~~ 0.4`
b. `~~ 0.8`
c. `~~ 0.4` d. `~~ 0.2`

A

`6.85`

B

`0.685`

C

`0.1043`

D

`6.50`

Text Solution

Verified by Experts

The correct Answer is:
B
Milli-mole of `HCl=1,000xx(1)/(2)=500`
Milli-mole of `HCl` given out `=(3.25)/(36.5)xx10^(23)= 89.04`
Milli-mole of `HCl` left `= 500-89.04=410.96`
New molarity `=(410.96)/(600)=0.685 M`
Promotional Banner

Topper's Solved these Questions

  • MOLE AND EQUIVALENT CONCEPT

    P BAHADUR|Exercise Exercise(3B)Objective problems|15 Videos

  • MOLE AND EQUIVALENT CONCEPT

    P BAHADUR|Exercise Exercise (4) Objective problems|20 Videos

  • MOLE AND EQUIVALENT CONCEPT

    P BAHADUR|Exercise Exercise (2) prevous year numberical problems|25 Videos

  • IONIC EQUILIBRIUM

    P BAHADUR|Exercise Exercise|85 Videos

  • RADIO ACTIVITY

    P BAHADUR|Exercise Exercies 9|99 Videos

Similar Questions

Explore conceptually related problems

One litre of a solution of N/2 HCl was heated in beaker and it was observed that when the volume of solution got reduce to 600 mL, 3.25 g of HCl was lost. Calculate the normality of the resulting solution.

Upon heating 1 L of 2 N HCl solution, 36.5 g of HCl is lost and the volume of solution resuces to 800 mL. Calculate . (a). The normality of the resultant solution. (b). The number of equivalents of HCl in 100 " mL of " the original solution..

P BAHADUR-MOLE AND EQUIVALENT CONCEPT-Exercise (3A) Objective problems:
  1. The solubility of K(2)SO(4) in water is 16 g at 50^(@)C. The minimum a...

    Text Solution

    |

  2. One litre of N//2 HCl solution was heated in a beaker. When the volume...

    Text Solution

    |

  3. The molarity of H(2)SO(4) is 18 M. Its density is 1.8 g mL^(-1). hence...

    Text Solution

    |

  4. Volume of 2 M HCl required to neutralise the solution containing 1"mol...

    Text Solution

    |

  5. 8 g of sulphur are burnt to form SO(2), which is oxidised by Cl(2) wat...

    Text Solution

    |

  6. The density of 1 M solution of NaCl is 1.0585 g mL^(-1). The molality ...

    Text Solution

    |

  7. The percentage of sodium in a breakfast careal labelled as 110 mg of s...

    Text Solution

    |

  8. Two element A (at.wt.75) and B(at.wt.16) combine to yield a compound. ...

    Text Solution

    |

  9. Calculate the number of oxalic acid molecules in 100 mL of 0.02 N oxal...

    Text Solution

    |

  10. Which sample contains the largest number of atoms?

    Text Solution

    |

  11. The total number of protons, electrons and neutrons in 12 g of .(6)C^(...

    Text Solution

    |

  12. 4.4 g of CO(2) and 2.24 "litre" of H(2) at STP are mixed in a containe...

    Text Solution

    |

  13. The hydrated salt, Na(2)SO(4)*nH(2)O undergoes 55.9% loss in weight on...

    Text Solution

    |

  14. In which mode of expression, the concentration of a solution remains i...

    Text Solution

    |

  15. The haemoglobin from the red blood corpuscles of most mammals contains...

    Text Solution

    |

  16. The pair of compounds which cannot exist in solution is:

    Text Solution

    |

  17. The mole of fraction of NaCl in a solution containing 1 "mole" of NaCl...

    Text Solution

    |

  18. 3.0 molal NaOH solution has a density of 1.110 g//mL. The molarity of ...

    Text Solution

    |

  19. How many atoms are contained in a mole of Ca(OH)(2)?

    Text Solution

    |

  20. Insulin contains 3.4% sulphur. Calculate minimum mol.wt. of insulin.

    Text Solution

    |