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Volume of 2 M HCl required to neutralise...

Volume of `2 M HCl` required to neutralise the solution containing `1"mole"` of `NH_(4)Cl` and `1 "mole"` of `NaOH` is:

A

`1 "litre"`

B

`2 "litre"`

C

`3 "litre"`

D

`1//2 "litre"`

Text Solution

Verified by Experts

The correct Answer is:
D
`(NH_(4)Cl)+NaOH+HClrarrNaCl+H_(2)O`
Milli-mole of `NaOH="Milli-mole of" HCl`
`1000xx2V_(("in"mL))`
`:. V=(1000)/(2)=500 mL`
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