`8 g` of sulphur are burnt to form `SO_(2)`, which is oxidised by `Cl_(2)` water. The solution is treated with `BaCl_(2)` solution. The amount of `BaSO_(4)` precipitated is:

Options

A. `1.0 "mole"`
B. `0.5 "mole"`
C. `0.75 "mole"`
D. `0.25 "mole"`

Answer

D

Explanation

`Soverset(O_(2))rarrSO_(2)overset(Cl_(2))rarrSO_(4)^(2-)overset(BaCl_(2))rarrBaSO_(4)`
One mole of `S` will give `1 "mole"` of `BaSO_(4)`
Mole of `BaSO_(4)` formed`=` moles of sulphur
`=(8)/(32)=(1)/(4)`