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The density of 1 M solution of NaCl is 1...

The density of `1 M` solution of `NaCl` is `1.0585 g mL^(-1)`. The molality of the solution is

A

`1.0585`

B

`1.0`

C

`0.10`

D

`0.0585`

Text Solution

Verified by Experts

The correct Answer is:
B
`m=("Mole of" NaCl)/("weight of solvent in" kg)=(1)/(1)=1`
`"wt. of solvent"="wt.of solution"-"wt. of" NaCl`
`=1.0585xx1000-58.5`
`=1058.5-58.5=100 g=1kg`
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