How many atoms are contained in a mole of `Ca(OH)_(2)`?

Options

A. `30xx6.02xx10^(23)` atoms/mol
B. `5xx6.02xx10^(23)`atoms/mol
C. `6xx6.02xx10^(23)`atoms/mol
D. none of these

Explanation

To determine how many atoms are contained in one mole of calcium hydroxide, \( Ca(OH)_2 \), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the formula**: The chemical formula for calcium hydroxide is \( Ca(OH)_2 \). This indicates that there is one calcium (Ca) atom, two hydroxide (OH) groups.

2. **Break down the hydroxide group**: Each hydroxide group (\( OH \)) consists of one oxygen (O) atom and one hydrogen (H) atom. Therefore, for two hydroxide groups, we have:
- Oxygen: \( 2 \times 1 = 2 \) oxygen atoms
- Hydrogen: \( 2 \times 1 = 2 \) hydrogen atoms

3. **Count the total number of atoms**: Now, we can count the total number of atoms in one mole of \( Ca(OH)_2 \):
- Calcium: 1 atom
- Oxygen: 2 atoms
- Hydrogen: 2 atoms

Total number of atoms = Calcium atoms + Oxygen atoms + Hydrogen atoms
\[ = 1 + 2 + 2 = 5 \text{ atoms} \]

4. **Calculate the number of atoms in a mole**: Since one mole of any substance contains \( 6.022 \times 10^{23} \) entities (Avogadro's number), the total number of atoms in one mole of \( Ca(OH)_2 \) is:
\[ 5 \times 6.022 \times 10^{23} \text{ atoms} \]

### Final Answer:
Thus, one mole of \( Ca(OH)_2 \) contains \( 5 \times 6.022 \times 10^{23} \) atoms.