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A compound has the molecular formula X(4...

A compound has the molecular formula `X_(4)O_(6)`. If `10 g "of" X_(4)O_(6)` has `5.72 g X`, atomic mass of `X` is:

A

`32 "amu"`

B

`37 "amu"`

C

`42 "amu"`

D

`98 "amu"`

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The correct Answer is:
To find the atomic mass of element X in the compound \(X_4O_6\), we can follow these steps: ### Step 1: Determine the total mass of the compound The total mass of the compound \(X_4O_6\) is given as \(10 \, g\). ### Step 2: Determine the mass of element X in the compound The mass of element X in the compound is given as \(5.72 \, g\). ### Step 3: Calculate the mass of oxygen in the compound To find the mass of oxygen in the compound, we subtract the mass of X from the total mass of the compound: \[ \text{Mass of O} = \text{Total mass} - \text{Mass of X} = 10 \, g - 5.72 \, g = 4.28 \, g \] ### Step 4: Calculate the number of moles of oxygen The atomic mass of oxygen (O) is \(16 \, g/mol\). To find the number of moles of oxygen in the compound, we use the formula: \[ \text{Moles of O} = \frac{\text{Mass of O}}{\text{Atomic mass of O}} = \frac{4.28 \, g}{16 \, g/mol} = 0.2675 \, mol \] ### Step 5: Determine the number of moles of the compound In the molecular formula \(X_4O_6\), there are 6 moles of oxygen for every mole of the compound. Therefore, the number of moles of the compound \(X_4O_6\) can be calculated as: \[ \text{Moles of } X_4O_6 = \frac{\text{Moles of O}}{6} = \frac{0.2675 \, mol}{6} = 0.04458 \, mol \] ### Step 6: Calculate the total mass of element X in the compound From the molecular formula \(X_4O_6\), we know that there are 4 moles of X for every mole of the compound. Thus, the moles of X can be calculated as: \[ \text{Moles of X} = 4 \times \text{Moles of } X_4O_6 = 4 \times 0.04458 \, mol = 0.17832 \, mol \] ### Step 7: Calculate the atomic mass of element X We know the mass of X in the compound is \(5.72 \, g\). The atomic mass of X can be calculated using the formula: \[ \text{Atomic mass of X} = \frac{\text{Mass of X}}{\text{Moles of X}} = \frac{5.72 \, g}{0.17832 \, mol} \approx 32.1 \, g/mol \] ### Final Answer The atomic mass of element X is approximately \(32.1 \, g/mol\). ---

To find the atomic mass of element X in the compound \(X_4O_6\), we can follow these steps: ### Step 1: Determine the total mass of the compound The total mass of the compound \(X_4O_6\) is given as \(10 \, g\). ### Step 2: Determine the mass of element X in the compound The mass of element X in the compound is given as \(5.72 \, g\). ...
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A certain compound has the molecular formula X_(4)O_(6) . If 10 g of X_(4) O_(6) has 5.72 g X , the atomic mass of X is

Objective question . i. A certains compound has the molecular formula X_(4) O_(6) . If 10 g of X_(4) O_(6) has 5.72 g X , then atomic mass of X is: a. 32 amu b. 42 amu c. 98 amu d. 37 amu ii. For 109% labelled oleum, if the number of moles of H_(2)SO_(4) and free SO_(3) be p and q , respectively, then what will be the value of (p - q)/(p + q) a. 1//9 b. 9 c. 18 d. 1//3 iii. Hydrogen peroxide in aqueous solution decomposes on warming to give oxygen according to the equation, 2H_(2) O_(2) (aq) rarr 2 H_(2) O (l) + O_(2) (g) Under conditions where 1 mol gas occupies 24 dm^(3), 100 cm^(3) of X M solution of H_(2) O_(2) produces 3 dm^(3) of O_(2) . Thus, X is a. 2.5 b. 0.5 c. 0.25 d. 1 iv. 4 g of sulphur is burnt to form SO_(2) which is oxidised by Cl_(2) water. The solution is then treated with BaCl_(2) solution. The amount of BaSO_(4) precipitated is: a. 0.24 mol b. 0.5 mol c. 1 mol d. 0.125 mol v. A reaction occurs between 3 moles of H_(2) and 1.5 moles of O_(2) to give some amount of H_(2) O . The limiting reagent in this reaction is a. H_(2) and O_(2) both b. O_(2) c. H_(2) d. Neither of them vi. 4 I^(ɵ) + Hg^(2+) rarr HgO_(4)^(-) , 1 mole each of Hg^(2+) and I^(ɵ) will form: a. 1 mol of HgI_(4)^(2-) b. 0.5 mol of HgI_(4)^(-2) 0.25 mol of HgI_(4)^(2-) 2 mol of HgI_(4)^(-2)

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P BAHADUR-MOLE AND EQUIVALENT CONCEPT-Exercise (3A) Objective problems:
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  2. One mole of potassium chlorate is thermally decomposed and excess of a...

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  3. A compound has the molecular formula X(4)O(6). If 10 g "of" X(4)O(6) h...

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  4. On repeated sparking, 10 mL of a mixture of carbon monoxide and nitrog...

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  5. Number of ions present in 2.0 "litre" of a solution of 0.8 M K(4)Fe(CN...

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  6. The molality of 1 L solution with x% H(2)SO(4) is equal to 9. The weig...

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  7. RH(2) ( ion exchange resin) can replace Ca^(2+)d in hard water as. R...

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  8. The total ionic strength (toal molarity of all ions containing 0.1M "o...

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  9. The pair of species having same percentage of carbon is:

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  10. The isotopic abundance of C-12 and C-14 "is" 98% and 2% respectively. ...

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  14. a. What is the volume of one molecule of water (density of H(2) O = 1 ...

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  15. If 224 mL of triatomic gas has a mass of 1 g at 273 K and 1 atm. Press...

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  17. The dehydration yield of cyclohexanol to cyclohexene is 75%. What woul...

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  18. The volume equivalent of CO(2) (at STP) in the reaction, NaHCO(3)+HC...

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  19. Potash alum and chrome alum are examples of:

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  20. Which of the following is not primary standard?

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