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The molality of 1 L solution with x% H(2...

The molality of `1 L` solution with `x% H_(2)SO_(4)` is equal to 9. The weight of the solvent present in the solution is `910 g`. The value of `x` is:

A

`90`

B

`80.3`

C

`40.13`

D

`9`

Text Solution

Verified by Experts

The correct Answer is:
B
`m=(axx1000)/(98xx910)=9`
`:. a= 802.62 g//"litre"`
`:. %` by weight `=80.26 g=X`
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