The total ionic strength (toal molarity of all ions containing `0.1M "of"CuSO_(4)` and `0.1 M "of" Al_(2)(SO_(4))_(3)` is:

Options

A. `0.2 M`
B. `0.7 M`
C. `0.8 M`
D. `1.2 M`

Answer

B

Explanation

One mole of `CuSO_(4)` gives `1 "mole of" Cu^(2+)` and `1 "mole of" SO_(4)^(2-)`. Also `1 "mole of" Al_(2)(SO_(4))_(3)` gives `2 "mole of" Al^(3+)` and `3"mole of" SO_(4)^(2-)`. Thus total moles of all the ions present in solution having `0.1 M of CuSO_(4)` and `0.1M of Al_(2)(SO_(4))_(3)` is
`0.1+0.1+0.2+0.3=0.7`