The total number of `AlF_(3)` molecule in a sample of `AlF_(3)` containing `3.01xx10^(23)` ions of `F^(-)` is:

Options

A. `9.0xx10^(24)`
B. `3.0xx10^(24)`
C. `7.5xx10^(23)`
D. `10^(23)`

Explanation

To find the total number of AlF₃ molecules in a sample containing \(3.01 \times 10^{23}\) ions of \(F^-\), we can follow these steps:

### Step 1: Understand the composition of AlF₃
Each molecule of aluminum fluoride (AlF₃) contains:
- 1 aluminum ion (Al³⁺)
- 3 fluoride ions (F⁻)

### Step 2: Calculate the number of AlF₃ molecules
Since each molecule of AlF₃ contains 3 fluoride ions, we can determine the number of AlF₃ molecules in the sample by dividing the total number of fluoride ions by the number of fluoride ions per molecule.

\[ \text{Number of AlF}_3 \text{ molecules} = \frac{\text{Total number of } F^- \text{ ions}}{\text{Number of } F^- \text{ ions per molecule of AlF}_3} \]

Substituting the values:
\[ \text{Number of AlF}_3 \text{ molecules} = \frac{3.01 \times 10^{23}}{3} \]

### Step 3: Perform the calculation
\[ \text{Number of AlF}_3 \text{ molecules} = 1.0033 \times 10^{23} \]

### Step 4: Final answer
Thus, the total number of AlF₃ molecules in the sample is approximately \(1.0033 \times 10^{23}\).

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