Amount of oxygen in `32.2 g` of `Na_(2)SO_(4).10H_(2)O` is:

Options

A. `20.8 g`
B. `26.71 g`
C. `2.24 g`
D. `2.08 g`

Explanation

To find the amount of oxygen in 32.2 g of Na₂SO₄·10H₂O, we will follow these steps:

### Step 1: Calculate the Molar Mass of Na₂SO₄·10H₂O

1. **Find the molar mass of each component:**
- Sodium (Na): 23 g/mol
- Sulfur (S): 32 g/mol
- Oxygen (O): 16 g/mol
- Hydrogen (H): 1 g/mol

2. **Calculate the molar mass of Na₂SO₄:**
- Na₂SO₄ = (2 × 23) + 32 + (4 × 16)
- = 46 + 32 + 64
- = 142 g/mol

3. **Calculate the molar mass of 10H₂O:**
- H₂O = (2 × 1) + 16 = 18 g/mol
- 10H₂O = 10 × 18 = 180 g/mol

4. **Total molar mass of Na₂SO₄·10H₂O:**
- Molar mass = 142 g/mol + 180 g/mol = 322 g/mol

### Step 2: Determine the Mass of Oxygen in Na₂SO₄·10H₂O

1. **Calculate the total number of oxygen atoms:**
- In Na₂SO₄, there are 4 oxygen atoms.
- In 10H₂O, there are 10 oxygen atoms.
- Total oxygen = 4 + 10 = 14 oxygen atoms.

2. **Calculate the mass of oxygen:**
- Mass of oxygen = Number of oxygen atoms × Molar mass of oxygen
- Mass of oxygen = 14 × 16 g/mol = 224 g/mol

### Step 3: Calculate the Amount of Oxygen in 32.2 g of Na₂SO₄·10H₂O

1. **Use the ratio of the mass of oxygen to the total mass of Na₂SO₄·10H₂O:**
- Ratio = Mass of oxygen / Molar mass of Na₂SO₄·10H₂O
- Ratio = 224 g / 322 g

2. **Calculate the mass of oxygen in 32.2 g of Na₂SO₄·10H₂O:**
- Mass of oxygen in 32.2 g = (224 g / 322 g) × 32.2 g
- = 22.4 g

### Final Answer:
The amount of oxygen in 32.2 g of Na₂SO₄·10H₂O is **22.4 g**.

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