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A gaseous alkane was exploded with oxyge...

A gaseous alkane was exploded with oxygen. The volume of `O_(2)` for complete combustion to `CO_(2)` formed was in the ratio of `7:4`. The molecular formula of alkane is:

A

`CH_(4)`

B

`C_(2)H_(6)`

C

`C_(3)H_(6)`

D

`C_(4)H_(10)`

Text Solution

Verified by Experts

The correct Answer is:
B
`C_(n)H_(2n+2)+[n+(n+1)/(2)]O_(2)rarrnCO_(2)+(n+1)H_(2)O`
`("Volume of" O_(2) "used")/("Volume of" CO_(2) "formed")=(7)/(4)`
`(n+(n+2)//2)/(n)=(7)/(4)`
`:. n=2` and alkane is `C_(2)H_(6)`.
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