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The radius of a water molecule having de...

The radius of a water molecule having density `1.0g mL^(-1)` is :

A

`1.925 Å`

B

`73.46Å`

C

`19.25Å`

D

`7.346Å`

Text Solution

Verified by Experts

The correct Answer is:
A
`V=4//3 pir^(3)`
Also volume of `1 "molecule"`
`=(18)/(6.023xx10^(23))mL ( :. 1 g=1 mL)`
`:. r^(3)=(3xx18)/(6.023xx10^(23)xx4xx3.14)`
`r=1.925xx10^(-8)cm`
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