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Total number of electrons present in 11....

Total number of electrons present in `11.2 litre` of `NH_(3)` at `STP` are:

A

`6.02 xx 10^(23)`

B

`3.01 xx 10^(23)`

C

`3.01 xx 10^(24)`

D

`5.1 xx 10^(24)`

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The correct Answer is:
To find the total number of electrons present in 11.2 liters of ammonia (NH₃) at standard temperature and pressure (STP), we can follow these steps: ### Step 1: Determine the number of moles of NH₃ in 11.2 liters at STP. At STP, 1 mole of any gas occupies 22.4 liters. Therefore, to find the number of moles in 11.2 liters, we can use the formula: \[ \text{Number of moles} = \frac{\text{Volume of gas}}{\text{Molar volume at STP}} = \frac{11.2 \, \text{liters}}{22.4 \, \text{liters/mole}} = 0.5 \, \text{moles} \] ### Step 2: Calculate the total number of electrons in one mole of NH₃. The molecular formula for ammonia (NH₃) indicates that it consists of one nitrogen (N) atom and three hydrogen (H) atoms. - Nitrogen (N) has 7 electrons. - Each Hydrogen (H) atom has 1 electron, and since there are 3 hydrogen atoms, they contribute a total of \(3 \times 1 = 3\) electrons. Thus, the total number of electrons in one molecule of NH₃ is: \[ \text{Total electrons in NH₃} = \text{Electrons from N} + \text{Electrons from H} = 7 + 3 = 10 \, \text{electrons} \] ### Step 3: Calculate the total number of electrons in 0.5 moles of NH₃. To find the total number of electrons in 0.5 moles of NH₃, we need to multiply the number of electrons in one mole by the number of moles: \[ \text{Total electrons} = \text{Number of moles} \times \text{Electrons per mole} \times \text{Avogadro's number} \] Where Avogadro's number (\(N_A\)) is approximately \(6.022 \times 10^{23}\) particles/mole. Thus, \[ \text{Total electrons} = 0.5 \, \text{moles} \times 10 \, \text{electrons/molecule} \times 6.022 \times 10^{23} \, \text{molecules/mole} \] Calculating this gives: \[ \text{Total electrons} = 0.5 \times 10 \times 6.022 \times 10^{23} = 3.011 \times 10^{24} \, \text{electrons} \] ### Final Answer: The total number of electrons present in 11.2 liters of NH₃ at STP is \(3.011 \times 10^{24}\) electrons. ---

To find the total number of electrons present in 11.2 liters of ammonia (NH₃) at standard temperature and pressure (STP), we can follow these steps: ### Step 1: Determine the number of moles of NH₃ in 11.2 liters at STP. At STP, 1 mole of any gas occupies 22.4 liters. Therefore, to find the number of moles in 11.2 liters, we can use the formula: \[ \text{Number of moles} = \frac{\text{Volume of gas}}{\text{Molar volume at STP}} = \frac{11.2 \, \text{liters}}{22.4 \, \text{liters/mole}} = 0.5 \, \text{moles} \] ...
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