In a compound `A_(x)B_(y)`:

Options

A. Mole of `A= "Mole of" B = "Mole of" A_(x)B_(y)`
B. Eq. of `A=Eq. "of" B=Eq. "of" A_(x)B_(y)`
C. `yxx"mole of" A=yxx"mole of" B=(x+y)xx"mole of" A_(x)B_(y)`
D. `yxx"mole of" A= yxx"mole of"B`

Answer

B

Explanation

Equal equivalent reacts together to give same equivalent of product.