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20 g of an acid furnishes 0.5 "mole of" ...

`20 g` of an acid furnishes `0.5 "mole of" H_(3)O^(+)` ions in its aqueous solution. The value of `1` equivalent of the acid will be:

A

`40 g`

B

`20 g`

C

`10 g`

D

`100 g`

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The correct Answer is:
To find the value of 1 equivalent of the acid, we can follow these steps: ### Step 1: Understand the relationship between moles and equivalents 1 equivalent of an acid is defined as the amount of acid that can furnish 1 mole of H⁺ ions (or H₃O⁺ ions in aqueous solution). ### Step 2: Calculate the number of equivalents in the given mass of acid Given that 20 g of the acid furnishes 0.5 moles of H₃O⁺ ions, we can determine the number of equivalents of the acid. - Since 0.5 moles of H₃O⁺ corresponds to 0.5 equivalents of the acid, we can say: \[ \text{Number of equivalents} = 0.5 \] ### Step 3: Calculate the equivalent weight of the acid To find the equivalent weight of the acid, we use the formula: \[ \text{Equivalent weight} = \frac{\text{Weight of acid}}{\text{Number of equivalents}} \] Substituting the known values: \[ \text{Equivalent weight} = \frac{20 \, \text{g}}{0.5} = 40 \, \text{g/equiv} \] ### Conclusion Thus, the value of 1 equivalent of the acid is **40 g**. ---

To find the value of 1 equivalent of the acid, we can follow these steps: ### Step 1: Understand the relationship between moles and equivalents 1 equivalent of an acid is defined as the amount of acid that can furnish 1 mole of H⁺ ions (or H₃O⁺ ions in aqueous solution). ### Step 2: Calculate the number of equivalents in the given mass of acid Given that 20 g of the acid furnishes 0.5 moles of H₃O⁺ ions, we can determine the number of equivalents of the acid. ...
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P BAHADUR-MOLE AND EQUIVALENT CONCEPT-Exercise (3A) Objective problems:
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  2. In a compound A(x)B(y):

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  3. 20 g of an acid furnishes 0.5 "mole of" H(3)O^(+) ions in its aqueous ...

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  4. Which is not a molecular formula?

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  5. 1.0 g of pure calcium carbonate was found to require 50 mL of dilute H...

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  6. 100 mL each of 0.5 N NaOH, N//5 HCl and N//10H(2)SO(4) are mixed toget...

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  7. Vapour density of a volatile substance is 4(CH(4)=1). Its molecular we...

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  8. The equivalent weight of iron in Fe(2)O would be:

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  9. 25 mL HNO(3). If the volumes are mixed with 75 mL of 4.0 M HNO(3). If ...

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  10. To what extent must a given solution containing 40 mg AgNO(3) per mL b...

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  11. An oxide of metal have 20% oxygen. The eq.wt. of oxide is:

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  12. How much water is to be added to dilute 10 mL of 10 N HCl to make it d...

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  13. If 250 mL of a solution contains 24.5 g H(2)SO(4) the molarity and nor...

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  14. 0.5 mole of H(2)SO(4) is mixed with 0.2 mole of Ca(OH)(2). The maximum...

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  15. A metal oxide has 40% oxygen. The equivalent weight of the metal is:

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  16. A solution contains Na(2)CO(3) and NaHCO(3). 10 mL of the solution req...

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  17. 0.7 g "of" Na(2)CO(3).xH(2)O were dissolved in water and the volume wa...

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  18. A sample of peanut oil weighing 1.5763 g is added to 25 mL "of" 0.4210...

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  19. Eq.wt. of an acid salt NaHSO(4) is:

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  20. When a metal is burnt, its weight is increased by 24%. The equivalent ...

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