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25 mL HNO(3). If the volumes are mixed w...

`25 mL HNO_(3)`. If the volumes are mixed with `75 mL` of `4.0 M HNO_(3)`. If the volumes are additive, the molarity of the final mixture would be:

A

`3.25 M`

B

`4.0 M`

C

`3.75 M`

D

`3.59 M`

Text Solution

Verified by Experts

The correct Answer is:
C
Meq. of `HNO_(3)=25xx3=75`,
Meq.of `HNO_(3)=75xx4=300`,
`:.` Total Meq. `=375`
Thus `375=Nxx100`
`:. N=3.75`
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