To what extent must a given solution containing `40 mg AgNO_(3) per mL` be diluted to yield a solution containing `6 mg AgNO_(3) per mL` :

Options

A. Each `mL` must be diluted to `2.5 mL`
B. To each `mL` of solution `2.5 mL` of water should be added
C. To `1.5 mL` of solution `2 mL` of water should be added
D. To `1.5 mL` of solution `1.5 mL` of water should be added

Answer

A

Explanation

Meq.of conc. `AgNO_(3)=` Meq. of dil.`AgNO_(3)`
i.e., `(40xx10^(-3))/(170)xx1=(16xx10^(-3))/(170)xxV`,
`:. V= 2.5 mL`