When a metal is burnt, its weight is increased by `24%`. The equivalent weight of the metal wil be:

Options

A. `25`
B. `24`
C. `33.3`
D. `76`

Explanation

To find the equivalent weight of the metal that increases in weight by 24% when burnt, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Weight Increase**:
When the metal is burnt, it reacts with oxygen to form a metal oxide. The weight of the metal increases by 24% due to the addition of oxygen.

2. **Set Up the Equation**:
Let the initial weight of the metal be \( x \). After burning, the weight of the metal becomes \( x + 0.24x = 1.24x \).

3. **Weight of Oxygen Added**:
The increase in weight due to the reaction with oxygen is given as:
\[ \text{Weight of oxygen added} = 1.24x - x = 0.24x \]
We know that this weight increase is equal to the weight of the oxygen that combined with the metal.

4. **Determine the Equivalent Weight**:
The weight of oxygen added (0.24x) can also be expressed in terms of the equivalent weight of the metal. The equivalent weight of the metal can be defined as the weight that combines with 8 grams of oxygen (since the equivalent weight of oxygen is 8 g, based on its n-factor of 2).

5. **Set Up the Relationship**:
From the problem, we know that:
\[ 0.24x = 8 \quad \text{(since the weight increase corresponds to the equivalent weight of oxygen)} \]

6. **Solve for \( x \)**:
Rearranging the equation gives:
\[ x = \frac{8}{0.24} = \frac{8 \times 100}{24} = \frac{800}{24} \approx 33.33 \]

7. **Conclusion**:
The equivalent weight of the metal is approximately \( 33.33 \) grams.

### Final Answer:
The equivalent weight of the metal is \( 33.33 \) grams.

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