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100 mL of mixture of NaOH and Na(2)SO(4)...

`100 mL` of mixture of `NaOH` and `Na_(2)SO_(4)` is neutralised by `10 mL` of `0.5 M H_(2) SO_(4)`. Hence, NaOH in `100 mL` solution is

A

`0.2 g`

B

`0.4 g`

C

`0.6 g`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
B
`Meq. of NaOH=10xx0.5xx2=10`
`:. (w)/(98//3)xx1000=10`
`:. w=0.4 g`
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