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0.05 moles of NaHCO(3) will react with h...

`0.05` moles of `NaHCO_(3)` will react with how many equivalent of `Mg(OH)_(2)`?

A

`0.2 Eq.`

B

`0.05 Eq.`

C

`0.02 Eq.`

D

`0.01 Eq.`

Text Solution

Verified by Experts

The correct Answer is:
B
`0.05` equivalent or mole of `NaHCO_(3)` requires `0.05` eq. of `Mg(OH)_(2)`.
`2NaHCO_(3)+Mg(OH)_(2)rarrMgCO_(3)+Na_(2)CO_(3)+2H_(2)O`
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