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Volume strength of H(2)O(2) labelled is ...

Volume strength of `H_(2)O_(2)` labelled is `10 vol`. What is normality of `H_(2)O_(2)`?

A

`1.79`

B

`12.79`

C

`0.79`

D

`5.6`

Text Solution

Verified by Experts

The correct Answer is:
A
`"Normality"=("Volume strength of"H_(2)O_(2))/(5.6)`
`:. N=(10)/(5.6)=1.79`
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