Weight of oxygen in `Fe_(2)O_(3)` and `FeO` in the simple ratio for the same amount of iron is:

Options

A. `1:2`
B. `2:1`
C. `3:2`
D. `1:3

Explanation

To find the weight of oxygen in `Fe_(2)O_(3)` and `FeO` in the simple ratio for the same amount of iron, follow these steps:

### Step 1: Determine the molar masses of the compounds
- **For `Fe_(2)O_(3)`**:
- Molar mass of Iron (Fe) = 56 g/mol
- Molar mass of Oxygen (O) = 16 g/mol
- In `Fe_(2)O_(3)`, there are 2 Fe and 3 O:
- Total mass of Fe = 2 × 56 = 112 g
- Total mass of O = 3 × 16 = 48 g

- **For `FeO`**:
- In `FeO`, there is 1 Fe and 1 O:
- Total mass of Fe = 1 × 56 = 56 g
- Total mass of O = 1 × 16 = 16 g

### Step 2: Equalize the amount of iron
To compare the weights of oxygen in both compounds for the same amount of iron, we need to equalize the amount of iron.

- Since `Fe_(2)O_(3)` has 112 g of iron, we need to have the same amount of iron in `FeO`.
- To achieve this, we multiply `FeO` by 2:
- New mass of `FeO` = 2 × (Fe + O) = 2 × (56 + 16) = 2 × 72 = 144 g
- This gives us 2 Fe (2 × 56 = 112 g) and 2 O (2 × 16 = 32 g).

### Step 3: Calculate the total weight of oxygen for both compounds
- **For `Fe_(2)O_(3)`**:
- Weight of oxygen = 48 g

- **For `FeO` (after multiplying by 2)**:
- Weight of oxygen = 32 g

### Step 4: Find the ratio of weights of oxygen
Now, we can find the ratio of the weights of oxygen in `Fe_(2)O_(3)` and `FeO`:
- Ratio of weight of oxygen in `Fe_(2)O_(3)` to weight of oxygen in `FeO` = 48 g : 32 g

### Step 5: Simplify the ratio
To simplify the ratio:
- 48 : 32 can be simplified by dividing both sides by 16:
- 48 ÷ 16 = 3
- 32 ÷ 16 = 2
- Thus, the simplified ratio is 3 : 2.

### Final Answer
The weight of oxygen in `Fe_(2)O_(3)` and `FeO` for the same amount of iron is in the ratio **3 : 2**.

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