Calculate the density `("in gm L"^(-1))` of a 3.60 M sulphuric acid solution that is 29 % `H_(2)SO_(4)` by mass `("molar mass = 98 g mol"^(-1))`

Options

A. `1.64`
B. `1.88`
C. `1.22`
D. `1.45`

Answer

C

Explanation

Let the density of solution be `'d'`
Molarity of solution given `=3.6`
i.e., `1` litre of solution contains `3.6 "moles"` of `H_(2)SO_(4)` or `1"litre"` of solution contains `3.6xx98 g` of `H_(2)SO_(4)`
Since, the solution is `29%` by mass.
`100 g` solution contains `29 g` of `H_(2)SO_(4)`
`(100)/(g)mL` solution contains `29 g` of `H_(2)SO_(4)`
`100 mL` solution contains `3.6xx98 g "of" H_(2)SO_(4)`
`1000 mL`, solution contains `3.6xx98g"of" H_(2)SO_(4)`
`therefore 3.6xx98=(29xxd)/(100)xx1000`
`therefore d=1.22`