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Find the number of g-molecules of oxygen...

Find the number of `g`-molecules of oxygen in `6.023xx10^(24)CO` molecules.

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To find the number of gram molecules of oxygen in \(6.023 \times 10^{24}\) molecules of carbon monoxide (CO), we can follow these steps: ### Step 1: Understand the relationship between CO and O2 From the balanced chemical reaction: \[ \text{CO} + \frac{1}{2} \text{O}_2 \rightarrow \text{CO}_2 \] We see that 1 mole of CO reacts with \(\frac{1}{2}\) mole of O2. This means that for every mole of CO, there is half a mole of O2 produced. ### Step 2: Calculate the number of moles of CO The number of molecules in a mole is given by Avogadro's number, \(6.023 \times 10^{23}\). To find the number of moles of CO in \(6.023 \times 10^{24}\) molecules, we use the formula: \[ \text{Number of moles} = \frac{\text{Number of molecules}}{\text{Avogadro's number}} \] Substituting the values: \[ \text{Number of moles of CO} = \frac{6.023 \times 10^{24}}{6.023 \times 10^{23}} = 10 \text{ moles of CO} \] ### Step 3: Calculate the number of moles of O2 Since 1 mole of CO corresponds to \(\frac{1}{2}\) mole of O2, we can find the number of moles of O2 as follows: \[ \text{Number of moles of O2} = \frac{1}{2} \times \text{Number of moles of CO} = \frac{1}{2} \times 10 = 5 \text{ moles of O2} \] ### Step 4: Convert moles of O2 to gram molecules The term "gram molecule" is synonymous with "mole". Therefore, the number of gram molecules of O2 is simply the number of moles of O2 calculated in the previous step: \[ \text{Number of gram molecules of O2} = 5 \] ### Final Answer The number of gram molecules of oxygen in \(6.023 \times 10^{24}\) CO molecules is **5**. ---

To find the number of gram molecules of oxygen in \(6.023 \times 10^{24}\) molecules of carbon monoxide (CO), we can follow these steps: ### Step 1: Understand the relationship between CO and O2 From the balanced chemical reaction: \[ \text{CO} + \frac{1}{2} \text{O}_2 \rightarrow \text{CO}_2 \] We see that 1 mole of CO reacts with \(\frac{1}{2}\) mole of O2. This means that for every mole of CO, there is half a mole of O2 produced. ...
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P BAHADUR-MOLE AND EQUIVALENT CONCEPT-Exercise 6 (INTEGER ANSWERS TYPE PROBLEMS)
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