Calculate the mass of `CaO` that shall be obtained by heating `20 kg` of `80%` pure limestone `(CaCO_(3))`.

Answer

9

Explanation

`underset(100 kg)(CaCO_(3))rarrunderset(56 kg)(CaO)+CO_(2)`
pure limestone `20 kg` of `80%=(20xx80)/(100)=16kg`

`:' 100 kg caCO_(3)` gives `=56 kg CaO`
`:. 16 kg CaCO_(3)` give `= (56 xx 16)/(100) = 8.96`
`~~ 9 kg CaO`