Home
Class 11
CHEMISTRY
Find the weight of H(2)SO(4) in 919 mL o...

Find the weight of `H_(2)SO_(4)` in `919 mL` of a solution of `0.2N` strength.

Text Solution

Verified by Experts

The correct Answer is:
9

` "Meq.of" H_(2)SO_(4)=(w)/("Eq.wt")xx1000=NxxV_(("in"mL))`
`=(w)/(49)xx1000=0.2xx919`
`therefore w=9g`
Promotional Banner

Topper's Solved these Questions

  • MOLE AND EQUIVALENT CONCEPT

    P BAHADUR|Exercise Exercise 7 Comprehension based objective problems|31 Videos
  • MOLE AND EQUIVALENT CONCEPT

    P BAHADUR|Exercise Exercise 8 Statements: Explanation type problems|11 Videos
  • MOLE AND EQUIVALENT CONCEPT

    P BAHADUR|Exercise Exercise (4) Objective problems|20 Videos
  • IONIC EQUILIBRIUM

    P BAHADUR|Exercise Exercise|85 Videos
  • RADIO ACTIVITY

    P BAHADUR|Exercise Exercies 9|99 Videos

Similar Questions

Explore conceptually related problems

Find the weight of H_(2) SO_(4) in 1200 mL of a solution of 0.2 N strength.

Find the weight of H_(2)SO_(4) in 1200mL of a solution of 0.4N strength.

Find out the weight of H_(2)SO_(4) in 150 mL, (N)/(7)H_(2)SO_(4) .

When 100 ml of 10 M solution of H_(2)SO_(4) and 100 ml of 1 0 M solution of NaOH are mixed the resulting solution will be

If the molecular weight of H_(2)SO_(4) is 98. The amount of acid present in 400 ml of 0.1 molar solution of acid will be

A solution of H_(2)O_(2) labelled as '20 V' was left open. Due to this some, H_(2)O_(2) decomposed and volume strength of the solution decreased . To determine the new volume strength of the H_(2)O_(2) solution, 10 mL of the solution was taken and it was diluted to 100 mL . 10 mL of this diluted solution was titrated against 25 mL of 0.0245 M KMnO_(4) solution under acidic condition. Calculate the volume strength of the H_(2)O_(2) solution .

A 5.0 mL of solution of H_(2)O_(2) liberates 0.508 g of iodine from acidified KI solution. Calculate the strength of H_(2)O_(2) solution in terms of volume strength at STP .

The formula weight of H_(2)SO_(4) is 98. The weight of the acid in 400 mL 0.1 M solution is

P BAHADUR-MOLE AND EQUIVALENT CONCEPT-Exercise 6 (INTEGER ANSWERS TYPE PROBLEMS)
  1. H(2)O(2) is marked 22.4 volume. How much of it is required to oxidise ...

    Text Solution

    |

  2. Calculate the weight of NaOH in 75 mill-equivalents.

    Text Solution

    |

  3. Calculate the normality of 0.74 g Ca(OH)(2) in 10 mL of solution.

    Text Solution

    |

  4. What is the strength in g//L of a solution of H(2)SO(4), 14 mL of whic...

    Text Solution

    |

  5. Find the weight of H(2)SO(4) in 919 mL of a solution of 0.2N strength.

    Text Solution

    |

  6. Calculate the volume of a solution of HCl containing 80.5 g of acids p...

    Text Solution

    |

  7. 1 g of an acid C(6)H(10)O(4) is completely neutralised by 0.768 g KOH....

    Text Solution

    |

  8. 0.9698 g of an acid are present in 300 mL of a solution. 10 mL of this...

    Text Solution

    |

  9. On being heated in oxygen, 3.120 g of a metal M convert to 4.560 g of ...

    Text Solution

    |

  10. 3.150 g of oxalic acid [(COOH)(2).xH(2)O] are dissolved in water and v...

    Text Solution

    |

  11. Find the concentration of 1.6N solution of H(2)O(2) in terms of volume...

    Text Solution

    |

  12. The equivalent weight of an element is 4. Its chloride has a vapour de...

    Text Solution

    |

  13. 2.68xx10^(-3) moles of solution containing anion A^(n+) require 1.61xx...

    Text Solution

    |

  14. What is the molality of acetic acid solution containing 6 g of acetic ...

    Text Solution

    |

  15. A bottle is labelled 122.5% oleum. 22.7 mL of Ca(OH)(2) is unknown mol...

    Text Solution

    |

  16. 15 g sample of an alloy containing Cu and Zn reacts completely with 3M...

    Text Solution

    |

  17. What is the 'n' factor or valency factor of ozone during the change: 2...

    Text Solution

    |

  18. A student of performs a titration with different burettes and finds ti...

    Text Solution

    |

  19. The volume (in mL) of 0.1M Ag NO(3) required for complete precipitatio...

    Text Solution

    |

  20. 29.2% (w//w) HCl stock, solution has a density of 1.25 g mL^(-1). The ...

    Text Solution

    |