Calculate the volume of a solution of `HCl` containing `80.5 g` of acids per litre would suffice for the exact neutralization of `NaOH` obtained by allowing `0.46 g` of metallic sodium to act upon water?

Answer

9

Explanation

`Na+H_(2)OrarrNaOH+(1)/(2)H_(2)`
`NaOH+HClrarrNaCl+H_(2)O`
Thus,
`Meq. "of" Na=Meq."of" NaOH` formed
`="Meq.of" HCl` used
`(0.46)/(23)xx100=(80.5)/(36.5)xxVrArrVapprox9.0mL`
`( :. "Meq. of" HCl=NxxV)`