`20 mL` of `0.2 M Al_(2) (SO_(4))_(3)` is mixed with `20 mL` of `0.6 M BaCl_(2)`. Calculate the concentration of each ion in solution.

Options

A. `0.6N, 0.6 N`
B. `0.2 N, 0.6 N`
C. `0.6 N, 0.2 N`
D. `0.2N, 0.2 N`

Answer

A

Explanation

`{:(,Al_(2)(SO_(4))_(3)+,BaCl_(2)rarr,BaSO_(4)darr+,AlCl_(3)),(Meq.at,20xx0.2xx6,20xx0.6xx2,0,0),(t=0,=24,=24,,),("Meq.after reaction",0,0,24,24):}` ,
`therefore [Al^(3+)]=(24)/(40)=0.6N`
`[Cl^(-)]=(24)/(40)=0.6N`