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A 6.90 M solution of KOH contains 30% by...

A `6.90 M` solution of `KOH` contains 30% by weight of `KOH`. Calculate the density of the solution.

A

`1.288g//mL`

B

`12.88 g //mL`

C

`0.1288g//mL`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A
Molarity of `KOH=(30)/(56xx(100)/(d))xx1000`
`therefore 6.90=(30xx10xxd)/(56)`
`therefore d=1.288g//mL`
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