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Statement 1 "mole" O(3)=N "molecule"O(3)...

Statement `1 "mole" O_(3)=N "molecule"O_(3)=3N` atoms of `O=48 g`
Explanation A mole is the amount of matter that contains as many as objects as the amount of atoms exactly in `12 g C^(12)`.

A

`S` is correct but `E` is wrong.

B

`S` is wrong but `E` is wrong.

C

Both `S` and `E` are correct and `E` is correct explanation of `S`.

D

Both `S` and `E` are correct but `E` is not correct explanation of `S.

Text Solution

Verified by Experts

The correct Answer is:
C
Explanation is correct reason for statements.
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How many moles are in 96 g O_(2)?

The number of carbon atoms in exactly 12 g C^(12) is called Avogadro's number , N_(A) (6.022 xx 10^(23)) . One mole is the amount of material which contains Avogradro's number of particle. These definitions emphasize that the mole refers to a fixed number of NA^(+) b Avogadro's number of atoms , electrons to refer to a mole of helium , a mole of electrons , or a mole of NA^(+) by Avogadro's number of atoms, electrons or ions respectively. On the other hand, phrases like "one mole of hydrogen" can be ambiguous , and should be restated as "one mole of hydroden atoms" or " one mole fo hydrogen molecules." But it is a matter of common practice among chemists , however , to let the name of the element stand for its mos common form. Thus one mole of O_(2) is frequently referred to as one mole of oxygen , whereas one moles of O is called one mole of oxygen atoms. Suppose if we take one mole molecules fo H_(2)SO_(4) then it contain 2 moles of H atom 1 mole of S atom and 4 moles of O atom. It can also be said that moles of oxygen molecules is (4)/(2) =2 mole. If a sample of CuSO_(4).5H_(2)O contains 3 moles of oxygen molecules , then fo H-atom present in the sample is :

The number of carbon atoms in exactly 12 g C^(12) is called Avogadro's number , N_(A) (6.022 xx 10^(23)) . One mole is the amount of material which contains Avogradro's number of particle. These definitions emphasize that the mole refers to a fixed number of NA^(+) b Avogadro's number of atoms , electrons to refer to a mole of helium , a mole of electrons , or a mole of NA^(+) by Avogadro's number of atoms, electrons or ions respectively. On the other hand, phrases like "one mole of hydrogen" can be ambiguous , and should be restated as "one mole of hydroden atoms" or " one mole fo hydrogen molecules." But it is a matter of common practice among chemists , however , to let the name of the element stand for its mos common form. Thus one mole of O_(2) is frequently referred to as one mole of oxygen , whereas one moles of O is called one mole of oxygen atoms. Suppose if we take one mole molecules fo H_(2)SO_(4) then it contain 2 moles of H atom 1 mole of S atom and 4 moles of O atom. It can also be said that moles of oxygen molecules is (4)/(2) =2 mole. Sulphur exists in different allotropic forms like S_(2) S_(6) 'and" S_(8) etc. If equal weight of these three ar taken in separate containers , then the ratio of number of atoms present in them is :

The number of carbon atoms in exactly 12 g C^(12) is called Avogadro's number , N_(A) (6.022 xx 10^(23)) . One mole is the amount of material which contains Avogradro's number of particle. These definitions emphasize that the mole refers to a fixed number of NA^(+) b Avogadro's number of atoms , electrons to refer to a mole of helium , a mole of electrons , or a mole of NA^(+) by Avogadro's number of atoms, electrons or ions respectively. On the other hand, phrases like "one mole of hydrogen" can be ambiguous , and should be restated as "one mole of hydroden atoms" or " one mole fo hydrogen molecules." But it is a matter of common practice among chemists , however , to let the name of the element stand for its mos common form. Thus one mole of O_(2) is frequently referred to as one mole of oxygen , whereas one moles of O is called one mole of oxygen atoms. Suppose if we take one mole molecules fo H_(2)SO_(4) then it contain 2 moles of H atom 1 mole of S atom and 4 moles of O atom. It can also be said that moles of oxygen molecules is (4)/(2) =2 mole. According to common practise , if you have Avogadro number of hydrogen molecules, then its mass is equal to :

Statement-I : 16g each O_(2) and O_(3) contains (N_(A))/(2) and (N_(A))/(3) atoms repectively Because Statement-II : 16g of O_(2) , and O_(3) contains same no. of atoms.

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