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25 mL of 0.107 M H(3)PO(4) was titrated...

`25 mL` of `0.107 M H_(3)PO_(4)` was titrated with `0.115 M` solution of `NaOH` to the end point identified by indicator bromocresol green.This required `23.1 mL`. The titration was repeated using phenolphthalein as indicator. This time `25 mL` of `0.107 M H_(3)PO_(4)` reuired `46.2 mL` of the `0.115 M NaOH`. What is the coefficient of `n` in this equation for each reaction?
`H_(3)PO_(4)+n OH^(-)rarr nH_(2)O+[H_(3-n)PO_(4)]^(n-)`

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The correct Answer is:
`n=2;`
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