A sample of `Mg` metal containing some `MgO` as impurity was dissolved in `125 mL` of `0.1N H_(2)SO_(4)`. The volume of `H_(2)` evolved at `27.5^(circ)C` and `1 atm` was `120.0 mL`. The resulting solution was found to be `0.02N` with respect to `H_(2)SO_(4)`. Calculate the weight of sample dissolved and the `%` by weight of pure `Mg` metal in sample. Neglect any change in volume.

Answer

`122.16 g, Mg=95.57%`;