`2.9 g` of a gas at `95^(@) C` occupied the same volume as `0.184 g` of hydrogen at `17^(@)C` at same pressure What is the molar mass of the gas ? .

Explanation

For gas `w = 2.9g T =95 +273 =368K`
For `H_(2) : w = 0.184g, T =17 + 273 =290K`
Since `V_(H_2) =V_(g), P_(H_2) =P_(g)`
`n_(g) T_(g) =n_(H_2) T_(H_2)`
`(2.9)/(m) xx 368 = (0.184)/(2) xx 290`
or ` m=40 mo1^(-1)` .