`0.75` mole solid `A_(4)` and `2` mole `O_(20` are heated in a sealed bulb to react completely and producing one mole of compound If product formed is also in gaseous state predict the ratio of final pressure at `600K` to initial pressure at `300K` .

Explanation

`{:(A_(4(s))+,O_(2(g))rarr,A_(x)O_(y(g))),(0.75,2,0),(0,0,1):}`
g -atoms of `A =0.75 xx 4 =3`
g-atoms of `O =2 xx 2 =4`
Thus compound formed is `A_(3)O_(4)`
Initially only `O_(2)` was there
`:. P_(i) xx V =2 xx R xx 300`
Finally only `A_(3)O_(4)` is there
`:. P_(f) xx V =1 xx R xx 600`
or `(P_(f))/(P_(i)) =1` .