What will be the pressure of the gas mixture when 0.5 litre of `H_(2)` at 0.8 bar and 2.0 litre of oxygen at 0.7 bar are introduced in a 1 litre vessel at `27^(@)C` .

Explanation

For `H_(2) n = (PV)/(RT) = (0.8 xx 0.5)/(RT) = (0.4)/(RT)`
For `O_(2) n = (0.7 xx 2.0)/(RT) = (1.4)/(RT)`
`:.` Total moles in mixture ` =(0.4)/(RT) + (1.4)/(RT) = (1.8)/(RT)`
Using `PV = nRT` for 1 litre container
Now `P_(mixture) xx 1 = (1.8)/(RT) xx RT = 1.8` bar