A vessel contains `14 g` of `H_(2)` and `96g` of `O_(2)` at `STP` Calculate
(a) The volume of vessel
(b) the pressure in the vessel when chemical reaction is induced in the vessel by passing electric spark till one of the gas is consumed The temperature brought back to `273 K` Neglect the volume of water formed .

Explanation

`n_(H_2) = (14)/(2) =7, n_(O_2) = (96)/(32) =3`
`:. PV = n_(T)RT`
`1 xx V =(7+3) xx 0.0821 xx 273`
`:. V =224.11` litre
`{:(,H_(2)+,½O_(2)rarr,H_(2)O,),("mole of"=0,7,3,0,),("mole after reaction",(7-6),0,6,),(,=1,,,):}`
Thus 1 mole of `H_(2)` is left
`:. Pxx 224.11 xx =1 xx 0.0821 xx 273`
`:. P_(H_(2)) = 0.10 atm` .