A long rectangular box is filled with `CI_(2)` (at wt 35.45) which is known to contain only `CI^(35)` and `CI^(37)` if the box could be divided by a partition and the two tpye of chlorine molecules put into the two compartments respectively calculate where should partition be madel if the pressure on both sides are to be equal Is this pressure the same as original pressure ? .

Explanation

Average mo1 wt `= (35n_(1) +37n_(2))/(n_(1)+n_(2)) = 35.45`
where `n_(1)` and `n_(2)` are moles of `CI^(35)` and `CI^(37)` isotopes
`:. (n_(1))/(n_(2)) = 3.44`
`:' P xx V_(1) = n_(1) RT`
`P xx V_(2) = n_(2) RT`
`:. (V_(1))/(V_(2)) = (n_(1))/(n_(2))`
Now volume prop moles when other things being equal and thus partition should be made at the point where moler ratio is 3.44:1 Pressure at this condition is same as the original pressure ( `:' V,T,n` are constant) .