The compressibility factor for a given real gas is 0.927 at `273 K` and `100 atm` Calculate the amount of gas required to fill a gas cylinder of 100 litre capacity under given conditions
(Mol weight of gas =30) .

Explanation

For real gas `PV =Z .nRT = (ZwRT)/(m)`
Givne compressibility factor `Z =0.927, T =273K`
`P =100 atm V =100 litre`
`:. 100 xx 100 = 0.027 xx (w)/(30) xx 0.0821 xx 273`
` w =14.439 xx 10^(3) g`
`w =14.439 kg` .