The cirtical constant for water are `374^(@)C` 218 atm and 0.0566 liter `mo1^(-1)` Calculate a,b and `R` .

Explanation

Given `T_(C) = 374^(@) C =374 + 273 = 647K`
`P_(C) = 218 atm`
`V_(C) = 0.0566 "litre" mo1^(-1)`
`b = (V_(C))/(3) = (0.0566)/(3) = 0.0189 "litre" mo1^(-1)`
`a =3P_(C) V_(C)^(2) =3 xx 218 xx (0.0566)^(2)`
` =2.095 litre^(2) "atm mo1"^(-2)`
`R = (8)/(3) (P_(C)V_(C))/(T_(C)) = (8 xx 218 xx 0.0566)/(3 xx 647)`
`0.05086 "litre atm"K^(-1) mo1^(-1)` .